b^2=2.56b

Solution for b^2=2.56b equation:

b^2=2.56b

We move all terms to the left:

b^2-(2.56b)=0

We add all the numbers together, and all the variables

b^2-(+2.56b)=0

We get rid of parentheses

b^2-2.56b=0

a = 1; b = -2.56; c = 0;
Δ = b2-4ac
Δ = -2.562-4·1·0
Δ = 6.5536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.56)-\sqrt{6.5536}}{2*1}=\frac{2.56-\sqrt{6.5536}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.56)+\sqrt{6.5536}}{2*1}=\frac{2.56+\sqrt{6.5536}}{2}
$